document.write( "Question 159971: Suppose a video store charges non-members $4 to rent a video. A membership costs $21 and then videos cost only $2.50 to rent. How many videos would you need to rent in order to jusitfy a membership? \n" ); document.write( "

Algebra.Com's Answer #117934 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Non member: ($4)(# of Vd)
\n" ); document.write( "Member: ($21)+($2.50)(# of Vd)
\n" ); document.write( "Equating the 2:
\n" ); document.write( " $\"4%2AVd=21%2B2.50%2AVd\"$ EQN 1
\n" ); document.write( " $\"4Vd-2.50Vd=21\"$
\n" ); document.write( " $\"1.5Vd=21\"$ -----> $\"cross%281.5%29Vd%2Fcross%281.5%29=cross%2821%2914%2Fcross%281.5%29\"$
\n" ); document.write( " $\"Vd=14\"$ ---------------> no. of videos to rent should be MORE than 14 to justify membership.
\n" ); document.write( "Okay, plug in 14 to EQN 1:
\n" ); document.write( " $\"4%2A14=21%2B2.50%2A14\"$
\n" ); document.write( " $\"56=21%2B35\"$
\n" ); document.write( " $\"56=56\"$ , see, at 14 rentals being a non member or a member will just be the same
\n" ); document.write( "Try 15 rentals:
\n" ); document.write( " $\"4%2A15=21%2B2.50%2A15\"$
\n" ); document.write( " $\"60=21%2B37.50\"$
\n" ); document.write( " $\"60=58.50\"$ , see, the higher the rentals, you start to save on being a member.
\n" ); document.write( "Try 20 for yourself.
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
\n" ); document.write( " \n" ); document.write( "

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