document.write( "Question 159792: two automobiles travel at the rate of 50kph and 30kph respectively. the faster travels 2 hours more than the other and goes 140 kilometers farther. find the distance traveled by each. \n" ); document.write( "
Algebra.Com's Answer #117909 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! two automobiles travel at the rate of 50kph and 30kph respectively. the faster travels 2 hours more than the other and goes 140 kilometers farther. find the distance traveled by each. \n" ); document.write( ": \n" ); document.write( "Let d = distance traveled by the slow car \n" ); document.write( "then \n" ); document.write( "(d+140) = distance traveled by the fast car \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = \n" ); document.write( ": \n" ); document.write( "Fast car time - 2hrs = slow car time \n" ); document.write( " \n" ); document.write( "Multiply equation by 150 to get rid of the denominators, results: \n" ); document.write( "3(d + 140) - 2(150) = 5d \n" ); document.write( ": \n" ); document.write( "3d + 420 - 300 = 5d \n" ); document.write( ": \n" ); document.write( "120 = 5d - 3d \n" ); document.write( "d = \n" ); document.write( "d = 60 km traveled by the slow car \n" ); document.write( ": \n" ); document.write( "60 + 140 = 200 km traveled by the fast car \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check the solutions; find the times of each car \n" ); document.write( "200/50 = 4 hrs \n" ); document.write( "60/30 = 2 hrs \n" ); document.write( "----------------- \n" ); document.write( "differ = 2 hrs \n" ); document.write( " \n" ); document.write( " |