document.write( "Question 159792: two automobiles travel at the rate of 50kph and 30kph respectively. the faster travels 2 hours more than the other and goes 140 kilometers farther. find the distance traveled by each. \n" ); document.write( "
Algebra.Com's Answer #117909 by ankor@dixie-net.com(22740)\"\" \"About 
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two automobiles travel at the rate of 50kph and 30kph respectively. the faster travels 2 hours more than the other and goes 140 kilometers farther. find the distance traveled by each.
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\n" ); document.write( "Let d = distance traveled by the slow car
\n" ); document.write( "then
\n" ); document.write( "(d+140) = distance traveled by the fast car
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\n" ); document.write( "Write a time equation; time = \"dist%2Fspeed\"
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\n" ); document.write( "Fast car time - 2hrs = slow car time
\n" ); document.write( "\"%28%28d%2B140%29%29%2F50\" - 2 = \"d%2F30\"
\n" ); document.write( "Multiply equation by 150 to get rid of the denominators, results:
\n" ); document.write( "3(d + 140) - 2(150) = 5d
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\n" ); document.write( "3d + 420 - 300 = 5d
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\n" ); document.write( "120 = 5d - 3d
\n" ); document.write( "d = \"120%2F2\"
\n" ); document.write( "d = 60 km traveled by the slow car
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\n" ); document.write( "60 + 140 = 200 km traveled by the fast car
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\n" ); document.write( "Check the solutions; find the times of each car
\n" ); document.write( "200/50 = 4 hrs
\n" ); document.write( "60/30 = 2 hrs
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\n" ); document.write( "differ = 2 hrs
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