document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159802>Question 159802</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to find the vertex for the following problem:\r<BR>\n" );
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document.write( "x^2+3x-4=0\r<BR>\n" );
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document.write( "All the help I could get would be appreciated.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117836 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the vertex is on the axis of symmetry\r<BR>\n" );
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document.write( "general eqn for axis is x=-b/(2a)\r<BR>\n" );
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document.write( "x=-3/(2*1)  __  x=-3/2\r<BR>\n" );
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document.write( "substituting  __  y = (-3/2)^2 + 3(-3/2) - 4  __  y = 9/4 - 9/2 -4  __  y = -25/4\r<BR>\n" );
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document.write( "vertex is (-3/2,-25/4) </SPAN>\n" );
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