document.write( "Question 159781: a rock climbing gym charges nonmembers $16 per day to use the gym and $8 per day for equipment rental. Members pay a yearly fee of $450 for unlimited rock climbing and $6 per day for equipment rental. Write and solve an equation to find how many times you must use the gym to justify becoming a member. \n" ); document.write( "
Algebra.Com's Answer #117820 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "RATE 1:
\n" ); document.write( "charge per session + equip't rental
\n" ); document.write( "$16/day + $8/day
\n" ); document.write( "RATE 2:
\n" ); document.write( "unlimited session + equip't rental
\n" ); document.write( "$450/yr + $6/day\r
\n" ); document.write( "\n" ); document.write( "Remember: x=no.of times (session) going to the gym
\n" ); document.write( ".
\n" ); document.write( "So equating RATE 1 & RATE 2:
\n" ); document.write( "\"16x%2B8x=450%2B6x\"
\n" ); document.write( "\"24x-6x=450\"
\n" ); document.write( "\"18x=450\" --------> \"cross%2818%29%2Fcross%2818%29=cross%28450%2925%2Fcross%2818%29\"
\n" ); document.write( "\"x=25\", number of sessions to go should be MORE than this in order to justify of becoming a member.
\n" ); document.write( "Let's see why?
\n" ); document.write( "RATE 1: =\"16%2A25%2B8%2A25\"
\n" ); document.write( "= \"400%2B200\"
\n" ); document.write( "= $600
\n" ); document.write( "RATE 2: = \"450%2B6%2A25\"
\n" ); document.write( "= \"450%2B150\"
\n" ); document.write( "= \"600\"
\n" ); document.write( "You see, if go 25 sessions, either RATE is okay. But if you go over 25, then RATE 2 is a better choice for unlimited rock climbing. Try 30 sessions you'll see.
\n" ); document.write( "Thank you
\n" ); document.write( "Jojo
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