document.write( "Question 159754: Use substitution to solve the system.\r
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document.write( "x - 7y = -10
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document.write( "3x + 2y = 10 \n" );
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Algebra.Com's Answer #117806 by KnightOwlTutor(293)![]() ![]() You can put this solution on YOUR website! x - 7y = -10 \n" ); document.write( "Add 7y to both sides\r \n" ); document.write( "\n" ); document.write( "x=-10+7Y\r \n" ); document.write( "\n" ); document.write( "replace x in the second equation with -10+7Y\r \n" ); document.write( "\n" ); document.write( "3(-10+7Y)+2Y=10\r \n" ); document.write( "\n" ); document.write( "Use the distributive property \n" ); document.write( "-30+21Y+2Y=10\r \n" ); document.write( "\n" ); document.write( "-30+23Y=10 \n" ); document.write( "add 30 to both sides of the equation\r \n" ); document.write( "\n" ); document.write( "23Y=40 \n" ); document.write( "divide both sides by 23\r \n" ); document.write( "\n" ); document.write( "Y=40/23 \n" ); document.write( "Replace y with 40/23 in the following equation in order to get a value for X \n" ); document.write( "x - 7y = -10\r \n" ); document.write( "\n" ); document.write( "x-7(40/23)=-10 \n" ); document.write( "X-280/23=-10\r \n" ); document.write( "\n" ); document.write( "Multiply each term by 23\r \n" ); document.write( "\n" ); document.write( "23X-280=-230 \n" ); document.write( "add 280 to both sides\r \n" ); document.write( "\n" ); document.write( "23X=50\r \n" ); document.write( "\n" ); document.write( "Divide both sides by 23\r \n" ); document.write( "\n" ); document.write( "X=50/23 \n" ); document.write( "Let's plug in the values to confirm\r \n" ); document.write( "\n" ); document.write( "x - 7y = -10\r \n" ); document.write( "\n" ); document.write( "50/23-7(40/23)=-10 (50-280)/23=-230/23=-10 \n" ); document.write( "3x + 2y = 10 3(50)/23 +2(40/23)=10 150/23+80/23=230/23=10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |