document.write( "Question 159699: can someone please help me with this problem:\r
\n" ); document.write( "\n" ); document.write( "Complete the square and write the equation in standard form. Then give the center and radius of the circle.\r
\n" ); document.write( "\n" ); document.write( "x^2^+ y^2 - 2x - 4y - 4 = 0
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Algebra.Com's Answer #117803 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2B+y%5E2+-+2x+-+4y+-+4+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "First, put the constant term on the right:
\n" ); document.write( "\"x%5E2%2B+y%5E2+-+2x+-+4y+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "Divide the coefficient on the first degree x term by 2. \"2%2F2+=+1\".\r
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\n" ); document.write( "\n" ); document.write( "Square the result and add that result to both sides. \"1%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B+y%5E2+-+2x+-+4y+%2B+1+=+4+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "Repeat the process with the coefficient on the first degree y term\r
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\n" ); document.write( "\n" ); document.write( "\"4%2F2=2\", \"2%5E2=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B+y%5E2+-+2x+-+4y+%2B+1+%2B+4+=+4+%2B+1+%2B+4\"\r
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\n" ); document.write( "\n" ); document.write( "Rearrange the terms:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1%2By%5E2-4y%2B4=9\"\r
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\n" ); document.write( "\n" ); document.write( "Now factor the x terms:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2x%2B1=%28x-1%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "And factor the y terms:\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2-4y%2B4=%28y-2%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Put the pieces back together:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29%5E2%2B%28y-2%29%5E2=9\"\r
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\n" ); document.write( "\n" ); document.write( "Now, use the fact that a circle of radius \"r\" centered at (\"h\",\"k\") has an equation \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\" to determine that your circle is centered at (\"1\",\"2\") and has a radius of \"sqrt%289%29=3\"
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