document.write( "Question 159748: The question reads: Paul and John are riding bicycles on the same path and in the same direction. Paul is going 5 mph and passes a lemonade stand at 12:00. John is going 7 mph and passes a lemonafe stand at 12:12. What time does John catch Paul. How far are they from the lemonade stand then?
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Algebra.Com's Answer #117794 by solver91311(24713) $\"\"$ $\"About$

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Presuming that both boys passed the same lemonade stand, since 12 minutes is $\"1%2F5\"$ hour, Paul will be 1 mile ahead of John when John passes the stand. John is travelling 2 miles per hour faster than Paul, so the question becomes how long would it take to go 1 mile at 2 miles per hour. 1 mile/2 mph = $\"1%2F2\"$ hour, or 30 minutes. 12:12 PM plus 30 minutes is 12:42. Paul is already 1 mile past the stand and still travelling 5 mph, so 30 minutes later he will have travelled an additional $\"5mph%2A%281%2F2%29hour=2.5mi\"$ . Hence John will catch Paul 3.5 miles past the lemonade stand. \n" ); document.write( "

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