document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159753>Question 159753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use a linear combination to solve the system.\r<BR>\n" );
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document.write( "5x + y = 6<BR>\n" );
document.write( "-5x + 3y = -22 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117787 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Add both the equations together\r<BR>\n" );
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document.write( "(5-5)X+(1+3)Y=6-22\r<BR>\n" );
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document.write( "4Y=-16<BR>\n" );
document.write( "Y=-4\r<BR>\n" );
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document.write( "To find X replace y with -4 in the first equation\r<BR>\n" );
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document.write( "5X-4=6\r<BR>\n" );
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document.write( "add 4 to both sides<BR>\n" );
document.write( "5X=10\r<BR>\n" );
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document.write( "divide both sides by 5<BR>\n" );
document.write( "X=2\r<BR>\n" );
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document.write( "to confirm replace x and y values in second equation\r<BR>\n" );
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document.write( "-5x + 3y = -22\r<BR>\n" );
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document.write( "-5(2)+3(-4)=-10-12=-22 </SPAN>\n" );
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