document.write( "Question 159749This question is from textbook Algebra 1
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document.write( ": Tell me if I am on the right track coming up with my solution to these linear equations using substitutions.
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document.write( "5c+3d=11
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document.write( "5c-d=5\r
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document.write( "5c-d=5
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document.write( "d=5c-5\r
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document.write( "5c+3(5c-5)=11
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document.write( "5c+15c-15=11
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document.write( "20c=-4
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document.write( "c=-5
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document.write( "I got stuck after this, am I on the right track? \n" );
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Algebra.Com's Answer #117786 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! You were on the right track, but got off on a siding...\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5c+3d=11 \n" ); document.write( "5c-d=5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5c-d=5 \n" ); document.write( "d=5c-5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5c+3(5c-5)=11 \n" ); document.write( "5c+15c-15=11 \n" ); document.write( "Up to this point, you were spot on, but\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "20c-15+15=11+15 \n" ); document.write( "20c=26 \n" ); document.write( "c=1.3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then\r \n" ); document.write( "\n" ); document.write( "d = 5(1.3) - 5 \n" ); document.write( "d = 6.5 - 5 = 1.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check\r \n" ); document.write( "\n" ); document.write( "5(1.3)+3(1.5)=6.5+4.5=11 Checks. \n" ); document.write( " |