document.write( "Question 159749This question is from textbook Algebra 1
\n" ); document.write( ": Tell me if I am on the right track coming up with my solution to these linear equations using substitutions.
\n" ); document.write( "5c+3d=11
\n" ); document.write( "5c-d=5\r
\n" ); document.write( "\n" ); document.write( "5c-d=5
\n" ); document.write( "d=5c-5\r
\n" ); document.write( "\n" ); document.write( "5c+3(5c-5)=11
\n" ); document.write( "5c+15c-15=11
\n" ); document.write( "20c=-4
\n" ); document.write( "c=-5
\n" ); document.write( "I got stuck after this, am I on the right track?
\n" ); document.write( "

Algebra.Com's Answer #117786 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
You were on the right track, but got off on a siding...\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5c+3d=11
\n" ); document.write( "5c-d=5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5c-d=5
\n" ); document.write( "d=5c-5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "5c+3(5c-5)=11
\n" ); document.write( "5c+15c-15=11
\n" ); document.write( "Up to this point, you were spot on, but\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "20c-15+15=11+15
\n" ); document.write( "20c=26
\n" ); document.write( "c=1.3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then\r
\n" ); document.write( "\n" ); document.write( "d = 5(1.3) - 5
\n" ); document.write( "d = 6.5 - 5 = 1.5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check\r
\n" ); document.write( "\n" ); document.write( "5(1.3)+3(1.5)=6.5+4.5=11 Checks.
\n" ); document.write( "
\n" );