document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159747>Question 159747</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An adjustable water sprinkler that sprays water in a circular pattern is placed at the center of a square field whose area is 1250 square feet. What is the shortest radius setting that can be used if the field is to be completely enclosed within the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117784 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(1250)=25sqrt(2) length of one side<BR>\n" );
document.write( "The diagonal of the field is 25sqrt(2)*sqrt(2)=50' because the hypotenuse of an isosceles right triangle equals the length of one of the sides times sqrt(2) (on the SAT test frequently).<BR>\n" );
document.write( "The shortest radius setting is 50/2=25'<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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