document.write( "Question 159597This question is from textbook Intermediate Algebra
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document.write( ": Five times the smallest of three consecutive odd integers is ten more than twice the largest. Find the integers. \n" );
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Algebra.Com's Answer #117703 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 5x=10+2(x+4) \n" ); document.write( "5x=10+2x+8 \n" ); document.write( "5x-2x=18 \n" ); document.write( "3x=18 \n" ); document.write( "x=18/3 \n" ); document.write( "x=6 answer for the smallest integer. \n" ); document.write( "Proof: \n" ); document.write( "5*6=10+2(6+4) \n" ); document.write( "30=10+2*10 \n" ); document.write( "30=10+20 \n" ); document.write( "30=30 \n" ); document.write( " |