document.write( "Question 159597This question is from textbook Intermediate Algebra
\n" ); document.write( ": Five times the smallest of three consecutive odd integers is ten more than twice the largest. Find the integers. \n" ); document.write( "
Algebra.Com's Answer #117703 by checkley77(12844)\"\" \"About 
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5x=10+2(x+4)
\n" ); document.write( "5x=10+2x+8
\n" ); document.write( "5x-2x=18
\n" ); document.write( "3x=18
\n" ); document.write( "x=18/3
\n" ); document.write( "x=6 answer for the smallest integer.
\n" ); document.write( "Proof:
\n" ); document.write( "5*6=10+2(6+4)
\n" ); document.write( "30=10+2*10
\n" ); document.write( "30=10+20
\n" ); document.write( "30=30
\n" ); document.write( "
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