document.write( "Question 159567: The product of two consecutive even positive integers is one hundred twenty. Find the two integers. \n" ); document.write( "

Algebra.Com's Answer #117670 by KnightOwlTutor(293) $\"\"$ $\"About$

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X=first even positive integer
\n" ); document.write( "X+2=second positive integer\r
\n" ); document.write( "\n" ); document.write( "The equation is (X)(X+2)=120\r
\n" ); document.write( "\n" ); document.write( "Use the distributive property
\n" ); document.write( "X^2+2X=120\r
\n" ); document.write( "\n" ); document.write( "subtract 120 from both sides\r
\n" ); document.write( "\n" ); document.write( "X^2+2X-120=0\r
\n" ); document.write( "\n" ); document.write( "This is a quadratic equation\r
\n" ); document.write( "\n" ); document.write( "Factor the equation \r
\n" ); document.write( "\n" ); document.write( "Find two numbers that multiplied together =-120
\n" ); document.write( "but when addded together gives you +2\r
\n" ); document.write( "\n" ); document.write( "I thought of 12 and 10\r
\n" ); document.write( "\n" ); document.write( "(X+12)(X-10)=0\r
\n" ); document.write( "\n" ); document.write( "Therefore the solution can be either -12 or 10\r
\n" ); document.write( "\n" ); document.write( "Since we are dealing with a positive even integer we cannot use -12 therefore the correct answer is 10 and 12
\n" ); document.write( "You can double check by plugging in the two integers\r
\n" ); document.write( "\n" ); document.write( "(10)(12)=120 \n" ); document.write( "

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