document.write( "Question 159559: 10 < x < 20 and 40 < y < 60, find the largest value of x^/2y
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Algebra.Com's Answer #117668 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Note: I'm assuming that \"x\" and \"y\" are integers\r
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\n" ); document.write( "\n" ); document.write( "If you meant to post $\"x%5E2%2Fy\"$ , then the largest value of $\"x%5E2%2Fy\"$ will have the largest possible $\"x%5E2\"$ (or the largest possible x). So this means that $\"x=19\"$ (if x is an integer). Also the largest value of $\"x%5E2%2Fy\"$ will have the smallest possible \"y\" value. So this means that $\"y=39\"$ \r
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\n" ); document.write( "\n" ); document.write( "So when $\"x=19\"$ and $\"y=39\"$ , this means that $\"x%5E2%2Fy=%2819%29%5E2%2F39=9.256\"$ which is the largest value when 10 < x < 20 and 40 < y < 60 \n" ); document.write( "

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