document.write( "Question 159536: if x+2y+3z=53 and 3x+2y+z=52 what is the value of x+y+z? \n" ); document.write( "
Algebra.Com's Answer #117656 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! if x+2y+3z=53 and 3x+2y+z=52 what is the value of x+y+z? \n" ); document.write( ": \n" ); document.write( "Add 'em up: \n" ); document.write( " x+2y+3z=53 \n" ); document.write( "3x+2y+ z=52 \n" ); document.write( "------------ \n" ); document.write( "4x + 4y + 4z = 105 \n" ); document.write( "Divide equation 4 \n" ); document.write( "x + y + z = \n" ); document.write( "x + y + z = 26 \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |