document.write( "Question 159558: Ten 6.0-V and 12-V batteries have a total voltage of 84 V.How many of each type are there ??? \n" ); document.write( "
Algebra.Com's Answer #117652 by KnightOwlTutor(293)\"\" \"About 
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X+Y=10 Total number of batteries\r
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\n" ); document.write( "\n" ); document.write( "X=# of 6.0 Volt batteries
\n" ); document.write( "10-X=3 0f 12 Volt batteries\r
\n" ); document.write( "\n" ); document.write( "#of batteriesX individual voltage =total voltage amount\r
\n" ); document.write( "\n" ); document.write( "The equation is
\n" ); document.write( "6(X)+12(10-X)=84\r
\n" ); document.write( "\n" ); document.write( "Use the distributive property\r
\n" ); document.write( "\n" ); document.write( "6X+120-12X=84\r
\n" ); document.write( "\n" ); document.write( "Subtract 120 from both sides\r
\n" ); document.write( "\n" ); document.write( "6X-12X=-36\r
\n" ); document.write( "\n" ); document.write( "Add the X terms\r
\n" ); document.write( "\n" ); document.write( "-6X=-36\r
\n" ); document.write( "\n" ); document.write( "X=6\r
\n" ); document.write( "\n" ); document.write( "Therefore you have 6 6 Volt batteries and 4 12V batteries \r
\n" ); document.write( "\n" ); document.write( "Double check bu plugging in values in the above expression
\n" ); document.write( "6(6)+12(4)=84\r
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