document.write( "Question 159555: How much pure acid should be mixed with 7 gallons of a 40% acid solution in order to get an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #117648 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much pure acid should be mixed with 7 gallons of a 40% acid solution in order to get an 80% acid solution? \n" ); document.write( "------------ \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.40*7 + 1.00x = 0.80(7+x) \n" ); document.write( "40*7 + 100x = 80(7+x) \n" ); document.write( "280 + 100x = 560 80x \n" ); document.write( "20x = 280 \n" ); document.write( "x = 14 gallons (amount of 100% acid that must be added) \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |