document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159494>Question 159494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose we wish to mix some 32% salt solution with some 58% salt solution to produce ten liters of 46.3% salt solution. How many liters of each of the starting solutions needs to be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117622 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117622\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .58x+.32(10-x)=.463*10<BR>\n" );
document.write( ".58x+3.2-.32x=4.63<BR>\n" );
document.write( ".26x=4.63-3.2<BR>\n" );
document.write( ".26x=1.43<BR>\n" );
document.write( "x=1.43/.26<BR>\n" );
document.write( "x=5.5 liters of 58% solution is used.<BR>\n" );
document.write( "10-5.5=4.5 liters of 32% solution is used.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".58*5.5+.32*4.5=.463*10<BR>\n" );
document.write( "3.19+1.44=4.63<BR>\n" );
document.write( "4.63=4.63 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );