document.write( "Question 159504: A tour-bus goes 90 miles to its destination. The rate returning is twice as fast as going. The time for a round trip is 3 hours. How fast does the tour-bus go on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #117620 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "Remember: \"Speed=S=distance%2Ftime\" ---> \"time=distance%2FSpeed\"... EQN 1
\n" ); document.write( "\"S%5B1%5D\"=Going destination
\n" ); document.write( "\"S%5B2%5D\"=Returning back=\"highlight%282S%5B1%5D%29\", twice as fast as going --> Condition 1
\n" ); document.write( "IMPORTANT: \"d%5B1%5D=90miles\", This distance is only for GOING for the trip.
\n" ); document.write( "ALSO: \"t%5B1%5D%2Bt%5B2%5D=3hours\", Total time going + time returning = 3 hours, in this eqn we get ----->\"t%5B1%5D=3-t%5B2%5D\", EQN 2
\n" ); document.write( "IMPORTANT: See EQN 1, time and Speed are inversely proportional. What does it mean? When Speed goes up, time goes down. Let's illustrate with this proportion:
\n" ); document.write( "\"S%5B1%5D%2FS%5B2%5D=t%5B2%5D%2Ft%5B1%5D\"
\n" ); document.write( "You see, when you double \"S%5B2%5D\", then \"t%5B1%5D\" doubles and vice versa, that's why INVERSELY PROPORTIONAL (not direct, not \"S%5B2%5D\" then \"t%5B2%5D\")
\n" ); document.write( "Hope you got it because it's important when we apply it in getting \"t%5B2%5D\"
\n" ); document.write( ".
\n" ); document.write( "With that said, as \"S%5B2%5D=2S%5B1%5D\", then \"t%5B1%5D=2t%5B2%5D\",EQN 3, oks?
\n" ); document.write( "Then we can equate EQN 2 and EQN 3 since both equal to \"t%5B1%5D\":
\n" ); document.write( "\"3-t%5B2%5D=2t%5B2%5D\"
\n" ); document.write( "\"3=2t%5B2%5D%2Bt%5B2%5D\"
\n" ); document.write( "\"3=3t%5B2%5D\" -----> \"cross%283%291%2Fcross%283%291=cross%283%29t%5B2%5D%2Fcross%283%29\"
\n" ); document.write( "\"t%5B2%5D=1hour\"
\n" ); document.write( "And, via EQN 2: \"t%5B1%5D=3-1=2hrs\"
\n" ); document.write( "Therefore we can continue in getting \"S%5B1%5D\" as per EQN 1:
\n" ); document.write( "\"S%5B1%5D=d%5B1%5D%2Ft%5B1%5D=90miles%2F2hours=cross%2890%2945%2Fcross%282%29\"
\n" ); document.write( "\"S%5B1%5D=45miles%2Fhr\" -----------------------> Speed going for the trip
\n" ); document.write( "And, as per Condition 1:
\n" ); document.write( "\"S%5B2%5D=2%2A45=90miles%2Fhr\" ------------------> Speed returning back
\n" ); document.write( "In doubt? go back EQN 1:
\n" ); document.write( "\"TotalTime=d%5B1%5D%2FS%5B1%5D%2Bd%5B2%5D%2FS%5B2%5D\"
\n" ); document.write( "\"3hours=90%2F45%2B90%2F90\"
\n" ); document.write( "\"3hours=2hours%2B1hour\"
\n" ); document.write( "\"3hours=3hours\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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