document.write( "Question 159495: A vat contains 450 gallons of 30% alcohol solution, but the manufacturer wants a 42.6% alcohol solution. How much solution must be drained and replaced with pure alcohol to obtain the desired results? \n" ); document.write( "
Algebra.Com's Answer #117598 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! A vat contains 450 gallons of 30% alcohol solution, but the manufacturer wants a 42.6% alcohol solution. How much solution must be drained and replaced with pure alcohol to obtain the desired results? \n" ); document.write( ". \n" ); document.write( "Let x = amount drained and replaced with pure alcohol \n" ); document.write( ". \n" ); document.write( "\"amount of alcohol added\" + \"amt of alcohol in original\" = \"desired mixture\" \n" ); document.write( "x + .30(450-x) = .426(450) \n" ); document.write( "x + 135 - .30x = 191.7 \n" ); document.write( ".70x + 135 = 191.7 \n" ); document.write( ".70x = 56.7 \n" ); document.write( "x = 81 gallons \n" ); document.write( " |