document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21855>Question 21855</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square piece of paper is folded in half vertically. If the resulting figure has a perimeter of 12 cm, what was the area of the original square?\r<BR>\n" );
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document.write( "I got 48.<BR>\n" );
document.write( "Thanks <BR>\n" );
document.write( "Cindy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11757 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11757\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET THE SIDE OF THE SQUARE BE =X<BR>\n" );
document.write( "WHEN IT IS FOLDED INTO HALF WE GET A RECTANGLE OF SIDE X ON ONE SIDE AND X/2 ON OTHER SIDE.ITS PERIMETER=X+X/2+X+X/2...TAKING LCM 2 <BR>\n" );
document.write( "(2X+X+2X+X)/2=6X/2=3X..BUT PERIMETER =12...SO<BR>\n" );
document.write( "3X=12 CM<BR>\n" );
document.write( "X=12/=4 CM.<BR>\n" );
document.write( "HENCE AREA OF SQUARE =A*A=4*4=16...CAN YOU PLEASE TELL HOW YOU GOT 48 SO THAT WE CAN CORRECT YOUR WORKING AND TELL WHERE YOU HAVE GONE WRONG. </SPAN>\n" );
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