document.write( "Question 159407: A man's boyhood lasted 1/6 of his life, he played football for the next 1/8 of his life, and he married 5 years after quitting football. A daughter was born after he had been married 1/12 of his life. The daughter lived 1/2 as many years as her father. The man died 6 years after his daughter. How old was the man when he died? Use a number line to illustrate the time. Then write an equation and solve it. \n" ); document.write( "
Algebra.Com's Answer #117550 by ankor@dixie-net.com(22740)\"\" \"About 
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A man's boyhood lasted 1/6 of his life, he played football for the next 1/8 of his life, and he married 5 years after quitting football. A daughter was born after he had been married 1/12 of his life. The daughter lived 1/2 as many years as her father. The man died 6 years after his daughter. How old was the man when he died? Use a number line to illustrate the time. Then write an equation and solve it.
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\n" ); document.write( "Let x = the final age of the guy
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\n" ); document.write( "Final age = Boyhood + football + 5 yr married + child's birth + child's life + 6 =
\n" ); document.write( "x = \"1%2F6\"x + \"1%2F8\"x + 5 + \"1%2F12\"x + \"1%2F2\"x + 6
\n" ); document.write( "Multiply equation by 24 to get rid of the denominators, results:
\n" ); document.write( "24x = 4x + 3x + 24(5) + 2x + 12x + 24(6)
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\n" ); document.write( "24x = 21x + 120 + 144
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\n" ); document.write( "24x - 21x = 264
\n" ); document.write( "x = \"264%2F3\"
\n" ); document.write( "x = 88 yrs his final age
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\n" ); document.write( "Check solution in original equation:
\n" ); document.write( "88 = \"1%2F6\"88 + \"1%2F8\"88 + 5 + \"1%2F12\"88 + \"1%2F2\"88 + 6
\n" ); document.write( "88 = 14\"2%2F3\" + 11 + 5 + 7\"1%2F3\" + 44 + 6
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\n" ); document.write( "Number line (approximate)
\n" ); document.write( "Born + Boyhood + football + 5yr + child's birth + child's life + 6
\n" ); document.write( "0--------------16---------26---31------38------------------------------------------82-----88
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