document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159384>Question 159384</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0130264857/algebrahomeworkh>Prentice Hall Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> thirteen years ago, Mary's age was 5/17 of Grace's age. Two years from now Mary will be 1/2 of Jim's age. Together all their ages add up to 118. Find their ages five years from now. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117520 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We know that 13 years ago Mary was 5/17 Grace's age. This is algebraically <BR>\n" );
document.write( "written as M-13=5/17G<BR>\n" );
document.write( "M=Mary's age now<BR>\n" );
document.write( "G=Grace's age now<BR>\n" );
document.write( "J=Jim's age now<BR>\n" );
document.write( "Two years from now Mary will be 1/2 of Jim's age. We write this algebraically as:<BR>\n" );
document.write( " 1/2J=(M+2)\r<BR>\n" );
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document.write( "We also know that J+M+G=118\r<BR>\n" );
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document.write( "Isolate J by mutilplying both sides by to get<BR>\n" );
document.write( "J=2(M+2)<BR>\n" );
document.write( "Isolate G by Multiplying both sides of the equation by 17/5 to get\r<BR>\n" );
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document.write( "17/5(M-13)=G\r<BR>\n" );
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document.write( "Substitute J=2(M+2)\r<BR>\n" );
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document.write( "and G=17/5(M-13)\r<BR>\n" );
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document.write( "into 2(M+2) +17/5(M-13) +M=118\r<BR>\n" );
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document.write( "Multiply all the terms by 5 to get rid of the denominator\r<BR>\n" );
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document.write( "10(M+2)+17(M-13)+5M=590\r<BR>\n" );
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document.write( "Use the distributive property<BR>\n" );
document.write( "10M+20+17M-221+5M=590\r<BR>\n" );
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document.write( "Combine like terms and simplify the equation.\r<BR>\n" );
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document.write( "(10+17+5)M-201=590\r<BR>\n" );
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document.write( "32M-201=590\r<BR>\n" );
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document.write( "Add 201 to both sides of the equation\r<BR>\n" );
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document.write( "32M=791\r<BR>\n" );
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document.write( "Divide by 32 on both sides<BR>\n" );
document.write( "and get 24.7 Round up and it would be 25\r<BR>\n" );
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document.write( "Plug in to see if it makes sense.\r<BR>\n" );
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document.write( "1/2J=(M+2)\r<BR>\n" );
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document.write( "Mary would be 27 and Jim would be 54\r<BR>\n" );
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document.write( "25+54+G=118\r<BR>\n" );
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document.write( "Grace would be 39\r<BR>\n" );
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document.write( "(25-13)=5/17(39)\r<BR>\n" );
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document.write( "12=11.5 Round up would be 12.\r<BR>\n" );
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document.write( "Therefore in 5 years Mary=30 Grace=44 Jim=59\r<BR>\n" );
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document.write( " \r<BR>\n" );
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document.write( " </SPAN>\n" );
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