document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159321>Question 159321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 0.460 inch diameter brass rod is 8'5 7/32 long. Round answers to A. and B. to 3 significant digits.<BR>\n" );
document.write( " A. Find the volume in cubic inches, of the rod.<BR>\n" );
document.write( " B.Compute the total weight of 40 rods. Brass weighs 0.300 pound per cubic inch. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117517 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117517\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "A. Find the volume in cubic inches, of the rod.<BR>\n" );
document.write( "Volume = (\"area of base\")* height<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Since the diameter is given as: 0.460 inch <BR>\n" );
document.write( "The radius is 1/2(diameter) = 0.230 inch<BR>\n" );
document.write( ".<BR>\n" );
document.write( "\"area of base\" = (pi)r^2 = (3.142)(0.230)^2 = (3.142)(0.0529) = 0.166 sq inches<BR>\n" );
document.write( "\"height\" = 8'5 7/32 = (8*12)+5+(7/32) = 96+5+(0.21875) = 101.21875 inches<BR>\n" );
document.write( "Volume then is:<BR>\n" );
document.write( "0.166 * 101.21875 = 16.802 cubic inches<BR>\n" );
document.write( ".<BR>\n" );
document.write( "B.Compute the total weight of 40 rods. Brass weighs 0.300 pound per cubic inch<BR>\n" );
document.write( "That would be:<BR>\n" );
document.write( "40 * 16.802 * 0.300 = 201.624 pounds </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );