document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159380>Question 159380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help solve\r<BR>\n" );
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document.write( "Translate to an algebra statement:\r<BR>\n" );
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document.write( "Five times the difference of a number and one yields the same result as twice the same number increased by three. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117516 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The algebraic equation is\r<BR>\n" );
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document.write( "5(X-1)=2X+3<BR>\n" );
document.write( "Use the distributive property\r<BR>\n" );
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document.write( "5X-5=2X+3\r<BR>\n" );
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document.write( "Subtract 2X from both sides of the equation\r<BR>\n" );
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document.write( "3X-5=3\r<BR>\n" );
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document.write( "Add 5 to both sides of the equation\r<BR>\n" );
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document.write( "3X=8\r<BR>\n" );
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document.write( "Divdie both sides by 8\r<BR>\n" );
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document.write( "X=8/3\r<BR>\n" );
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document.write( "Replace all X in the above equation to confirm\r<BR>\n" );
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document.write( "5(8/3-1)=2(8/3) + 3\r<BR>\n" );
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document.write( "replace 1 with 3/3 amd 3 with 9/3\r<BR>\n" );
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document.write( "5(8/3-3/3) =2(8/3) + 9/3\r<BR>\n" );
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document.write( "5(5/3)=16/3 +9/3\r<BR>\n" );
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document.write( "25/3=25/3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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