document.write( "Question 159357: A mixture containing 6% boric acid is to be mixed with 4 liters of a mixture which is 25% boric acid in order to obtain a solution which is 12% boric acid. How much of the 6% solution must be used? \n" ); document.write( "
Algebra.Com's Answer #117492 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A mixture containing 6% boric acid is to be mixed with 4 liters of a mixture which is 25% boric acid in order to obtain a solution which is 12% boric acid. How much of the 6% solution must be used? \n" ); document.write( "--------------------------------- \n" ); document.write( "Acid EQUATIOn: 0.06x + 0.25*4 = 0.12(x+4) \n" ); document.write( "6x + 100 = 12x + 48 \n" ); document.write( "6x = 52 \n" ); document.write( "x = 8 2/3 liters (amt. of 6% solution that must be added) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |