document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159217>Question 159217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1)	A shipment of 40 laptop computers containing 6 defective ones. The shipping department selects seven of these laptops and rejects the entire shipment if one or more are defective. <BR>\n" );
document.write( "a) How many selections can be made?<BR>\n" );
document.write( "b) How many of these selection will contain no defective computers?<BR>\n" );
document.write( "c) How many selection will contain at least two defective ones?\r<BR>\n" );
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document.write( "2)	By playing Scrabble we ended up with the five remaining letters B, A, R, R, E. In how many ways can three of these five letters be arranged in a row if at least one of the letters is R?\r<BR>\n" );
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document.write( "3)	In how many ways can the letters of the word STATISTICS be arranged in a similar text where the first and the last letters of the word are fixed but the remaining letters inside are arranged arbitrarily?  \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117488 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1a) nCr(40,7)=n!/(n-r)!r!=18,643,560 selections can be made.<BR>\n" );
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document.write( "b) nCr(34,7)=5,379,616 selections that wont find a defective one.<BR>\n" );
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document.write( "c) <BR>\n" );
document.write( "nCr(6,2)*nCr(34,5)<BR>\n" );
document.write( "=15*278256<BR>\n" );
document.write( "=4,173,840 will contain 2 defective ones.<BR>\n" );
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document.write( "2)containing 1 r: nPr(4,3)=n!/(n-r)!=24 without the permutation of \"bae\" (not allowed) 3!=6<BR>\n" );
document.write( "24-6=18<BR>\n" );
document.write( "containing 2r's: 3 ways to arrange 3 letters among the 2 r's: 3*3=9<BR>\n" );
document.write( "9+18=27 ans.<BR>\n" );
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document.write( "3)We actually have the arrangement of \"tatistic\" which has 3 t's and 2 i's.<BR>\n" );
document.write( "P=n!/r[t]!*r[i]!=8!/3!2!=8*7*6*5*4/2=3360<BR>\n" );
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document.write( "Ed<BR>\n" );
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