document.write( "Question 159329: a chemist needs 5 liters of a 50% salt solution. All he has available is a 20% salt solution and a 70% salt solution. How many liters of each of the two solutions should he mix to obtain his desired solutions? \n" ); document.write( "
Algebra.Com's Answer #117466 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a chemist needs 5 liters of a 50% salt solution. All he has available is a 20% salt solution and a 70% salt solution. How many liters of each of the two solutions should he mix to obtain his desired solutions? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 70% solution \n" ); document.write( ": \n" ); document.write( "It says a total of 5 liters required, therefore \n" ); document.write( "(5-x) = amt of 20% solution \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Write the decimal equiv equation \n" ); document.write( ".70x + .20(5-x) = .50(5) \n" ); document.write( ": \n" ); document.write( ".70x + 1 - .20x = 2.5 \n" ); document.write( "; \n" ); document.write( ".7x - .2x = 2.5 - 1 \n" ); document.write( ".5x = 1.5 \n" ); document.write( "x = 3 liters of 70% solution, then obviously, 2 liters of 20% solution \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution solution: \n" ); document.write( ".7(3) + .2(2) = .5(5) \n" ); document.write( "2.1 + .4 = 2.5 \n" ); document.write( " |