document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159242>Question 159242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hey,<BR>\n" );
document.write( "could you please solve this problem for me. and thank you.\r<BR>\n" );
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document.write( "A rectangular field is to be enclosed and divided into two sections by a fence <BR>\n" );
document.write( "parallel to one of the sides using a total of 600 m of fencing. what is the <BR>\n" );
document.write( "maximum area that can be enclosed and what dimensions will give this area?\r<BR>\n" );
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document.write( "i will be waiting for your answer,\r<BR>\n" );
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document.write( "and thank you,<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117454 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular field is to be enclosed and divided into two sections by a fence<BR>\n" );
document.write( "parallel to one of the sides using a total of 600 m of fencing. What is the<BR>\n" );
document.write( "maximum area that can be enclosed and what dimensions will give this area? <BR>\n" );
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document.write( "Let x = the length of the rectangle<BR>\n" );
document.write( "Let w = the width<BR>\n" );
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document.write( "Two sections are required, therefore 3w of fence required<BR>\n" );
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document.write( "2x + 3w = 600<BR>\n" );
document.write( "also we can write it:<BR>\n" );
document.write( "3w = {600-2x)<BR>\n" );
document.write( "w = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28600-2x%29%29%2F3 ALIGN=MIDDLE  ALT=\"%28%28600-2x%29%29%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "w = 200 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x<BR>\n" );
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document.write( "Find the area;<BR>\n" );
document.write( "A = x*w<BR>\n" );
document.write( "Replace w with above expression:<BR>\n" );
document.write( "A = x(200 - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x)<BR>\n" );
document.write( "A = 200x - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282%2F3%29x%5E2 ALIGN=MIDDLE  ALT=\"%282%2F3%29x%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "This is a quadratic equation; if we find the axis of symmetry we will know<BR>\n" );
document.write( "what value of x gives maximum area:<BR>\n" );
document.write( ";<BR>\n" );
document.write( "Axis of symmetry formula: x = -b/(2a)<BR>\n" );
document.write( "In our equation, a=(-2/3); b=200; therefore;<BR>\n" );
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document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-200%29%2F%282%2A%28-2%2F3%29%29 ALIGN=MIDDLE  ALT=\"%28-200%29%2F%282%2A%28-2%2F3%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-200%29%2F%28-4%2F3%29%29 ALIGN=MIDDLE  ALT=\"%28-200%29%2F%28-4%2F3%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-200+%2A+%28-3%2F4%29 ALIGN=MIDDLE  ALT=\"-200+%2A+%28-3%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = +150 meters is the length that give max area<BR>\n" );
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document.write( "Find the max area by substituting 150 for x in the area equation<BR>\n" );
document.write( "A = 200(150) - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F3 ALIGN=MIDDLE  ALT=\"2%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >*150^2<BR>\n" );
document.write( "A = 30000 - 15000<BR>\n" );
document.write( "A = 15,000 sq/m is the max area<BR>\n" );
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document.write( "The dimensions of the rectangle: 150 by 100 meters [2(150) + 3(100) = 600] </SPAN>\n" );
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