document.write( "Question 159309: I am stumped on this problem. 3x^2-x-1=0. I am needing to solve it by either quadratic equation or finding the square root. Has to be completely worked out with all steps. \r
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\n" ); document.write( "Renee
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Algebra.Com's Answer #117452 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2-x-1=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=3\", \"b=-1\", and \"c=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-1%29+%2B-+sqrt%28+%28-1%29%5E2-4%283%29%28-1%29+%29%29%2F%282%283%29%29\" Plug in \"a=3\", \"b=-1\", and \"c=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+%28-1%29%5E2-4%283%29%28-1%29+%29%29%2F%282%283%29%29\" Negate \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1-4%283%29%28-1%29+%29%29%2F%282%283%29%29\" Square \"-1\" to get \"1\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1--12+%29%29%2F%282%283%29%29\" Multiply \"4%283%29%28-1%29\" to get \"-12\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+1%2B12+%29%29%2F%282%283%29%29\" Rewrite \"sqrt%281--12%29\" as \"sqrt%281%2B12%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+13+%29%29%2F%282%283%29%29\" Add \"1\" to \"12\" to get \"13\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281+%2B-+sqrt%28+13+%29%29%2F%286%29\" Multiply \"2\" and \"3\" to get \"6\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%281%2Bsqrt%2813%29%29%2F%286%29\" or \"x+=+%281-sqrt%2813%29%29%2F%286%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x+=+%281%2Bsqrt%2813%29%29%2F%286%29\" or \"x+=+%281-sqrt%2813%29%29%2F%286%29\" \r
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\n" ); document.write( "\n" ); document.write( "which approximate to \"x=0.768\" or \"x=-0.434\"
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