document.write( "Question 159295: 1)one of two complementary angles has a measure that is six more than twice the
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document.write( "other's. Find teh measure of the larger angle.\r
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document.write( "this is what i have: X= 6+(90-X)+2(90-X) and i got 42 degrees? \r
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document.write( "2) the measure of the supplement of an angle is five times that of the angle's complement. Find the measure of the complement.\r
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document.write( "this is what i have: (180-X)=5(90-X) and my answer is completely wrong\r
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document.write( "If you could help me i would really appreciate it, thanks \n" );
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Algebra.Com's Answer #117449 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! 1)one of two complementary angles has a measure that is six more than twice the \n" ); document.write( "other's. Find teh measure of the larger angle. \n" ); document.write( ". \n" ); document.write( "Let x = the larger angle \n" ); document.write( "then because they are complementary: \n" ); document.write( "90-x = the smaller angle \n" ); document.write( ". \n" ); document.write( "then from: \"one of two complementary angles has a measure that is six more than twice the other's\" \n" ); document.write( "x = 2(90-x)+6 \n" ); document.write( "x = 180-2x+6 \n" ); document.write( "x = 186-2x \n" ); document.write( "3x = 186 \n" ); document.write( "x = 62 degrees\r \n" ); document.write( "\n" ); document.write( "2) the measure of the supplement of an angle is five times that of the angle's complement. Find the measure of the complement. \n" ); document.write( ". \n" ); document.write( "Let x = the angle \n" ); document.write( "180-x = the supplement of the angle \n" ); document.write( ". \n" ); document.write( "180-x = 5x \n" ); document.write( "180 = 6x \n" ); document.write( "30 = x (the angle) \n" ); document.write( ". \n" ); document.write( "Supplement of the angle: \n" ); document.write( "180-x = 180-30 = 150 degrees \n" ); document.write( " |