document.write( "Question 159295: 1)one of two complementary angles has a measure that is six more than twice the
\n" ); document.write( "other's. Find teh measure of the larger angle.\r
\n" ); document.write( "\n" ); document.write( "this is what i have: X= 6+(90-X)+2(90-X) and i got 42 degrees? \r
\n" ); document.write( "\n" ); document.write( "2) the measure of the supplement of an angle is five times that of the angle's complement. Find the measure of the complement.\r
\n" ); document.write( "\n" ); document.write( "this is what i have: (180-X)=5(90-X) and my answer is completely wrong\r
\n" ); document.write( "\n" ); document.write( "If you could help me i would really appreciate it, thanks
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Algebra.Com's Answer #117449 by nerdybill(7384)\"\" \"About 
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1)one of two complementary angles has a measure that is six more than twice the
\n" ); document.write( "other's. Find teh measure of the larger angle.
\n" ); document.write( ".
\n" ); document.write( "Let x = the larger angle
\n" ); document.write( "then because they are complementary:
\n" ); document.write( "90-x = the smaller angle
\n" ); document.write( ".
\n" ); document.write( "then from: \"one of two complementary angles has a measure that is six more than twice the other's\"
\n" ); document.write( "x = 2(90-x)+6
\n" ); document.write( "x = 180-2x+6
\n" ); document.write( "x = 186-2x
\n" ); document.write( "3x = 186
\n" ); document.write( "x = 62 degrees\r
\n" ); document.write( "\n" ); document.write( "2) the measure of the supplement of an angle is five times that of the angle's complement. Find the measure of the complement.
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\n" ); document.write( "Let x = the angle
\n" ); document.write( "180-x = the supplement of the angle
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\n" ); document.write( "180-x = 5x
\n" ); document.write( "180 = 6x
\n" ); document.write( "30 = x (the angle)
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\n" ); document.write( "Supplement of the angle:
\n" ); document.write( "180-x = 180-30 = 150 degrees
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