document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159285>Question 159285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You invest $6000 in two accounts paying 9% and 6% anual interest.  At the end of the year, the total interest from these investments was $480. How much was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117432 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117432\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     You invest $6000 in two accounts paying 9% and 6% anual interest. At the end of the year, the total interest from these investments was $480. How much was invested at each rate?<BR>\n" );
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document.write( "Let x = amount invested at 9%<BR>\n" );
document.write( "then because the total invested was $6000 then<BR>\n" );
document.write( "6000-x = amount invested at 6%<BR>\n" );
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document.write( "And, because the total interest amount at the end of the year was $480:<BR>\n" );
document.write( ".09x + .06(6000-x) = 480<BR>\n" );
document.write( ".09x + 360 - .06x = 480<BR>\n" );
document.write( ".03x + 360 = 480<BR>\n" );
document.write( ".03x = 120<BR>\n" );
document.write( "x = $4000 (amount invested at 9%)<BR>\n" );
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document.write( "Amount invested at 6%:<BR>\n" );
document.write( "6000-x = 6000-4000 = $2000 (amount invested at 6%)  <BR>\n" );
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