document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159267>Question 159267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4y=(x+y+10)<BR>\n" );
document.write( "what does x and y equal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117409 by </B><A HREF=/tutors/aboutme.mpl?userid=t_as87><B>t_as87(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=t_as87><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to get all the like terms together on each side... <BR>\n" );
document.write( "so 4y = x + y + 10<BR>\n" );
document.write( "Subtract y from both sides to get<BR>\n" );
document.write( "3y = x + 10<BR>\n" );
document.write( "Now divide both sides by 3<BR>\n" );
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document.write( "if you want a formula for x<BR>\n" );
document.write( "using the 2nd equation: x = 3y - 10 </SPAN>\n" );
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