document.write( "Question 159258This question is from textbook Algebra And Trigonometry
\n" ); document.write( ": Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have? \n" ); document.write( "
Algebra.Com's Answer #117404 by nerdybill(7384)\"\" \"About 
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Mary has $3.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and five more nickels than dimes, how many coins of each type does she have?
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\n" ); document.write( "Let q = number of quarters
\n" ); document.write( "then from \"she has twice as many dimes as quarters\"
\n" ); document.write( "2q = number of dimes
\n" ); document.write( "and from \"five more nickels than dimes\"
\n" ); document.write( "2q+5 = number of nickels
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\n" ); document.write( "Since she has a total of $3.00:
\n" ); document.write( ".25q + .10(2q) + .05(2q+5) = 3.00
\n" ); document.write( ".25q + .20q + .10q + .25 = 3.00
\n" ); document.write( ".55q + .25 = 3.00
\n" ); document.write( ".55q = 2.75
\n" ); document.write( "q = 2.75/.55
\n" ); document.write( "q = 5 (number of quarters)
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\n" ); document.write( "number of dimes:
\n" ); document.write( "2q = 2(5) = 10 (number of dimes)
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\n" ); document.write( "number of nickels:
\n" ); document.write( "2q+5 = 2(5)+5 = 10 + 5 = 15 (number of nickels)
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