document.write( "Question 159241: find the equation of the line that contains point (8,-1) and is perpedicular to the line y= 1/4x + 3 \n" ); document.write( "

Algebra.Com's Answer #117384 by checkley77(12844) $\"\"$ $\"About$

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(8,-1)
\n" ); document.write( "Y=X/4+3 THIS LINE HAS A SLOPE (m)=1/4.
\n" ); document.write( "THE PERPENDICULAR LINE WILL HAVE A SLOPE=4.
\n" ); document.write( "-1=4*8+b
\n" ); document.write( "b=-1-32
\n" ); document.write( "b=-33
\n" ); document.write( "THUS THE LINE EQUATION FOR THE LINE THROUGH (8,-1) WITH A SLOPE=4 IS:
\n" ); document.write( "Y=4X-33.
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-6%2C+10%2C+-40%2C+10%2C+4x+-33%29+\"$ (graph 300x200 pixels, x from -6 to 10, y from -40 to 10, 4x -33).
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