document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159237>Question 159237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using data from 1996-1998, the annual number of cars sold at a certain dealership can be modeled by the formula y=4x+5,<BR>\n" );
document.write( "Where y is the number of cars, in thousands,sold x years after 1996. According to this formula, in which years will the number of cars sold exceed 45 thousand? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117374 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117374\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 45,000 means that y = 45, since y = 1,000's of cars.<BR>\n" );
document.write( "45 = 4x+5 Subtract 5 from both sides.<BR>\n" );
document.write( "40 = 4x Divide both sides by 4.<BR>\n" );
document.write( "x = 10 Now add 10 to 1996 to get 2006.<BR>\n" );
document.write( "So, in 2006 45,000 cars will be sold, then in 2007 the number of cars sold will exceed 45,000, so the answer is 2007 and later.<BR>\n" );
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