document.write( "Question 159133: Suppose that the function P = 13 + 14 ln x, represents the perecentage of inbound e-mail in the US. that is considered Spam, where x represents the number of years after 2000.
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document.write( "Use this model to determine in how many years(to two decimal places) it will take for the percentage to reach 95%, provided that law enforcement regarding spammers does not change. \n" );
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Algebra.Com's Answer #117371 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! P = percentage = 95 \n" ); document.write( "13+14*ln(x) = 95 \n" ); document.write( "ln(x) = (95-13)/14 \n" ); document.write( "ln(x) = 5.857142857 \n" ); document.write( " \n" ); document.write( "y = ln(x) = 5.857142857, so y = 5.857142857 \n" ); document.write( "equation for \n" ); document.write( "use the calculator to solve for \n" ); document.write( "answer becomes x = 349.7235051 \n" ); document.write( "substituting in the original equation of \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "solving for ln(349.7235051) using the calculator, we get \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "95 = 95. \n" ); document.write( "answer is 349.72 years rounding to the nearest hundredth. \n" ); document.write( "now that we know how far out x has to go to satisfy the equation, we can graph it as follows: \n" ); document.write( "range of x = -1 to 400 where x represents years from 2000. \n" ); document.write( "range of y = -10 to 100 where y represents percent. \n" ); document.write( "----------------------------------------------------- \n" ); document.write( "graph looks like this \n" ); document.write( "please scan below the graph for further comments. \n" ); document.write( "----------------------------------------------------- \n" ); document.write( " \n" ); document.write( "----------------------------------------------------- \n" ); document.write( "range of x had to start from - something in order for the x-axis to display properly. \n" ); document.write( "range of y had to start from - something in order for the y-axis to display properly \n" ); document.write( "the formula of \n" ); document.write( "-------------------------------------------- \n" ); document.write( "based on the formula as shown, x = 349.72 rounded to the nearest hundredth of a year. \n" ); document.write( "that year will be 2000 + 349.72 = 2349.72 based on the formula provided.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |