document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159218>Question 159218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x2 = 3y2 + 5 , x - 3 + 5 = 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117355 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-3+5=0  simplify to get x+2=0 subtract 2 from both sides and get x=-2\r<BR>\n" );
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document.write( "replace each x with -2. When you square a -number the result is positive. \r<BR>\n" );
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document.write( "2(-2)^2=3y^2+5      8=3y^2+5 \r<BR>\n" );
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document.write( "Subtract 5 from both side and you get 3=3y^2\r<BR>\n" );
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document.write( "Divide both sides by 3<BR>\n" );
document.write( "1=y^2 y =1 or -1. </SPAN>\n" );
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