document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159205>Question 159205</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073534961/algebrahomeworkh>Elementary Statistics</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 4.5 ( 2, 16, 32)\r<BR>\n" );
document.write( "\n" );
document.write( "2. How many ways can a basebal manager arrange a batting order of 9 player? <BR>\n" );
document.write( "   I did 9!= 362,880  please let me know if this is correct. \r<BR>\n" );
document.write( "\n" );
document.write( "16. An inspector must select 3 tests to perform in a certain order on a manufactured part. He has a choice of 7 tests. How many ways can he perform 3 different tests?<BR>\n" );
document.write( "   I did 7P3 = 7!/(7-3)! = 7!/4! = 210  Please let me know if this is correct. \r<BR>\n" );
document.write( "\n" );
document.write( "32. If a person can select 3 presents from 10 presents under a christmas tree, how many different combinations are there?<BR>\n" );
document.write( "   I did 10C3 = 10!/(10-3)!3!= 10!/7!3!= 10*9*8*7!/7!*3*2*1= 10*3*4=120  <BR>\n" );
document.write( "   Please let me know if this is correct.   \r<BR>\n" );
document.write( "\n" );
document.write( "Section 4-6 problem number 6\r<BR>\n" );
document.write( "\n" );
document.write( "6. A package contains 12 resistors, 3 of which are defective. If 4 are selected, fin the probability of getting<BR>\n" );
document.write( " <BR>\n" );
document.write( "   a. No defective resistors<BR>\n" );
document.write( "   b. 1 Defective resistor<BR>\n" );
document.write( "   c. 3 Defective resistors\r<BR>\n" );
document.write( "\n" );
document.write( "  for a.  P(no defectives)= 9C4/12C4=126/495 and then I got confused.\r<BR>\n" );
document.write( "\n" );
document.write( "  for b   P(1 defective) = 1- P(no defectives)<BR>\n" );
document.write( "                         = 1- 9C4/12C4<BR>\n" );
document.write( "                         = 1- 126/595<BR>\n" );
document.write( "                         Then I get confuse becaue I'm not sure how to<BR>\n" );
document.write( "                         subtract from the one. <BR>\n" );
document.write( "  <BR>\n" );
document.write( "for c. P(3 defective) = 3C3*9C3/12C4 = 94/495 I think i'm supposed to reduce it <BR>\n" );
document.write( "       but im not sure how or if this is correc. <BR>\n" );
document.write( " \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117346 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please read the comments:\r<BR>\n" );
document.write( "\n" );
document.write( "4.5 ( 2, 16, 32) <BR>\n" );
document.write( "2. How many ways can a basebal manager arrange a batting order of 9 player? <BR>\n" );
document.write( "I did 9!= 362,880 please let me know if this is correct.\r<BR>\n" );
document.write( "\n" );
document.write( "GOOD WORK<BR>\n" );
document.write( " <BR>\n" );
document.write( "16. An inspector must select 3 tests to perform in a certain order on a manufactured part. He has a choice of 7 tests. How many ways can he perform 3 different tests?<BR>\n" );
document.write( "I did 7P3 = 7!/(7-3)! = 7!/4! = 210 Please let me know if this is correct.\r<BR>\n" );
document.write( "\n" );
document.write( "GOOD WORK<BR>\n" );
document.write( " <BR>\n" );
document.write( "32. If a person can select 3 presents from 10 presents under a christmas tree, how many different combinations are there?<BR>\n" );
document.write( "I did 10C3 = 10!/(10-3)!3!= 10!/7!3!= 10*9*8*7!/7!*3*2*1= 10*3*4=120 <BR>\n" );
document.write( "Please let me know if this is correct. \r<BR>\n" );
document.write( "\n" );
document.write( "GOOD WORK<BR>\n" );
document.write( "Section 4-6 problem number 6 <BR>\n" );
document.write( "6. A package contains 12 resistors, 3 of which are defective. If 4 are selected, fin the probability of getting\r<BR>\n" );
document.write( "\n" );
document.write( "a. No defective resistors<BR>\n" );
document.write( "b. 1 Defective resistor<BR>\n" );
document.write( "c. 3 Defective resistors <BR>\n" );
document.write( "for a. P(no defectives)= 9C4/12C4=126/495 \r<BR>\n" );
document.write( "\n" );
document.write( "GOOD WORK\r<BR>\n" );
document.write( "\n" );
document.write( "and then I got confused. <BR>\n" );
document.write( "for b P(1 defective) = 1- P(no defectives) (WRONG)<BR>\n" );
document.write( "= 1- 9C4/12C4<BR>\n" );
document.write( "= 1- 126/595<BR>\n" );
document.write( "Then I get confuse becaue I'm not sure how to<BR>\n" );
document.write( "subtract from the one. \r<BR>\n" );
document.write( "\n" );
document.write( "Answer:<BR>\n" );
document.write( "P(1 defective)=P(1 def, 3 no def)=(3C1)(9C3)/12C4 =252/495 =28/55\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "for c. P(3 defective) = 3C3*9C3/12C4 = 94/495 I think i'm supposed to reduce it but im not sure how or if this is correc. (WRONG)\r<BR>\n" );
document.write( "\n" );
document.write( "Solution:\r<BR>\n" );
document.write( "\n" );
document.write( "P(3 defective)=P(3 def, 1 no def)=(3C3)(9C1)/12C4=9/495=1/55\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );