document.write( "Question 159065: Suppose that the number of new homes built, H, in a city over a period of time, t, is graphed on a rectangular coordinate system where time is on the horizontal axis. Suppose that the number of homes built can be modeled by an exponential function, H= p * at , where p is the number of new homes built in the first year recorded. If you were a homebuilder looking for work, would you prefer that the value of a to be between 0 and 1 or larger than 1? Explain your reasoning.
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Algebra.Com's Answer #117298 by gonzo(654)\"\" \"About 
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the answer is if it's \"a%2Ax\", any a value is ok but the bigger the x value the better. if it's \"a%5Ex\", any value > 1 is good because there will be growth, and any value < 1 is not good because there will be no growth.
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\n" ); document.write( "to show you, i'll graph 5 equations with different (a) values used in each equation starting with a value of \"a+%3C+1\" and ending with a value of \"a+%3E+1\".
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\n" ); document.write( "so that the graphs will show the proper x-axis values and the proper y-axis values, i had to cross the origin with both x and y values.
\n" ); document.write( "for your purposes, you just need to look at the values where x >= 0.
\n" ); document.write( "disregard the values where x < 0 since they are there only to force the x-axis and y-axis to show up properly and have no other meaning for the discussion.
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\n" ); document.write( "in both of these graphs, i am showing the total number of houses projected each year. any growth will be the number of houses in that year minus the number of houses in the previous year.
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\n" ); document.write( "for linear growth, the general equation will be \"y+=+%28a%2Ax%29%2A%28h%29%2B%28h%29\"
\n" ); document.write( "where
\n" ); document.write( "y is the total number of homes in each year (thousands).
\n" ); document.write( "x is the number of years.
\n" ); document.write( "a is the multiplication factor for each year.
\n" ); document.write( "h is the starting number of houses in thousands.
\n" ); document.write( "h will be set to 100 (thousand).
\n" ); document.write( "the additional h is required to make the number of houses equal to 100 (thousand) when x = 0.
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\n" ); document.write( "for the first equation, a is set to .25
\n" ); document.write( "for the second equation, a is set to .5
\n" ); document.write( "for the third equation, a is set to .75
\n" ); document.write( "for the 4th equation, a is set to 1.00
\n" ); document.write( "for the 5th equation, a is set to 1.25
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\n" ); document.write( "scan down below the graph for more information.
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\n" ); document.write( "the growth of homes in each year is the number of houses in that year minus the number of houses in the previous year.
\n" ); document.write( "as a gets larger, the number of houses required in a year goes higher.
\n" ); document.write( "for example,
\n" ); document.write( "in year 10 with a = .25, the number of houses is 350.
\n" ); document.write( "in year 10 with a = .75, the number of houses is 850.
\n" ); document.write( "in year 10 with a = 1.25, the number of houses is 1350.
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\n" ); document.write( "for exponential growth, the general equation will be \"y+=+%28a%5Ex%29%2A%28h%29%29\"
\n" ); document.write( "where
\n" ); document.write( "y is the total number of homes in each year.
\n" ); document.write( "x is the number of years.
\n" ); document.write( "a is the base factor that will be raised to the x power for each year.
\n" ); document.write( "h is the starting number of houses in thousands.
\n" ); document.write( "h will be set to 100 (thousand).
\n" ); document.write( "the additional h is not required here because a^0 = 1 for all values of a.
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\n" ); document.write( "for the first equation, a is set to .25
\n" ); document.write( "for the second equation, a is set to .5
\n" ); document.write( "for the third equation, a is set to .75
\n" ); document.write( "for the 4th equation, a is set to 1.00
\n" ); document.write( "for the 5th equation, a is set to 1.25
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\n" ); document.write( "scan down below the graph for more information.
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\n" ); document.write( "with an exponential factor, interesting things happen.
\n" ); document.write( "when a is > 1, the growth takes off.
\n" ); document.write( "when a = 1 there is no growth.
\n" ); document.write( "when a < 1 there is actually a decrease in the number of houses required each year.
\n" ); document.write( "if we take year 6 as an example, we get the following values:
\n" ); document.write( "when a = .25, \"y=.25%5E6%2A100\" which equals .0244....., a number very close to 0.
\n" ); document.write( "when a = .50, \"y+=+.5%5E6%2A100\" which equals 1.5625, a number still very close to 0.
\n" ); document.write( "when a = .75 \"y+=+.75%5E6%2A100\" which equals 17.7978..., a number that is further away from 0 but still less then the starting value of 100.
\n" ); document.write( "when a = 1.00 \"y+=+1.0%5E6%2A100\" which equals 100. the number of houses required each year remains the same.
\n" ); document.write( "when a = 1.25 \"y+=+1.25%5E6%2A100\" which equals 381.469....
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\n" ); document.write( "as x gets larger, any value of a less than 1 will tend towards 0.
\n" ); document.write( "take x = 100
\n" ); document.write( ".25^100 = 6.223.....^-61 which is a very small number and will keep getting smaller as x gets larger.
\n" ); document.write( ".75^100 = 3.207.....^-13 which is still avery small number and will keep getting smaller as x gets larger.
\n" ); document.write( "1.0^100 = 1 and will always be 1 as x gets larger because 1 to any power = 1.
\n" ); document.write( "1.25^100 = 4.909...^9 which is a very big number and will keep getting bigger as x gets large\r
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