document.write( "Question 159161: a + b =1 a^-1 + b^-1 = 1 prove a = b and a^-1 = b^-1\r \n" );
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document.write( "I have that \r \n" );
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document.write( "a = b / (b-1) \r \n" );
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document.write( "b = 1-a\r \n" );
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document.write( "plugging in b to a\r \n" );
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document.write( "I get a = (1-a)/a\r \n" );
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document.write( "set those equal \r \n" );
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document.write( "(1-a)/a = b/(b-1)\r \n" );
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document.write( "can't solve any further \n" );
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Algebra.Com's Answer #117297 by jim_thompson5910(35256) You can put this solution on YOUR website! I'm not sure if you have the right equations. If , then this means that becomes ===> which is NOT true for all values of \"a\". So double check the problem. \n" );
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