document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159159>Question 159159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A drama club's production of \"Oklahoma!\" is going to cost $1,250 to produce. How many tickets will they need to sell for $8.00 each to make a profit of at least $830.00? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117280 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     A drama club's production of \"Oklahoma!\" is going to cost $1,250 to produce. How many tickets will they need to sell for $8.00 each to make a profit of at least $830.00?<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let n = number of tickets sold<BR>\n" );
document.write( ".<BR>\n" );
document.write( "\"ticket sales\" = \"production costs\" + \"profit\"<BR>\n" );
document.write( "8n = 1250+830<BR>\n" );
document.write( "8n = 2080<BR>\n" );
document.write( "n = 2080/8<BR>\n" );
document.write( "n = 260 tickets must be sold<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );