document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159153>Question 159153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \"find the measure of an angle its measure is 5 times as large as its supplement\"\r<BR>\n" );
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document.write( "\"find the measure of an angle if its measure is 10 more than four times its complement\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117279 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem expects that you know:<BR>\n" );
document.write( "Two angles are complementary if the sum of their angles equal 90.<BR>\n" );
document.write( "Two angles are supplementary if the sum of their angles equal 180.<BR>\n" );
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document.write( "\"find the measure of an angle its measure is 5 times as large as its supplement\"<BR>\n" );
document.write( "Let x = measure of the angle<BR>\n" );
document.write( "then 180-x = supplement of the angle<BR>\n" );
document.write( "and from: \"the measure of an angle its measure is 5 times as large as its supplement\" we get:<BR>\n" );
document.write( "x = 5(180-x)<BR>\n" );
document.write( "x = 900-5x<BR>\n" );
document.write( "6x = 900<BR>\n" );
document.write( "x = 900/6<BR>\n" );
document.write( "x = 150 degrees\r<BR>\n" );
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document.write( "\"find the measure of an angle if its measure is 10 more than four times its complement\"<BR>\n" );
document.write( "Let x = measure of an angle<BR>\n" );
document.write( "then 90-x = complement of the angle<BR>\n" );
document.write( "and from: \"the measure of an angle if its measure is 10 more than four times its complement\" we get<BR>\n" );
document.write( "x = 4(90-x) + 10<BR>\n" );
document.write( "x = 360 - 4x + 10<BR>\n" );
document.write( "5x = 370<BR>\n" );
document.write( "x = 74 degrees<BR>\n" );
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