document.write( "Question 23167: When I am as old as my father is now, I shall be five times as old as my son is now. By then my son will be eight years older than I am now. The combinded ages of my father and myself are 100 years. How old is my son?\r
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document.write( "Father=x Myself=y Son=s\r
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document.write( " x=5s x+y=100 5s=y+8 y/5=s
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document.write( " 5(y/5)+y=100
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document.write( "I just don't know how to solve this. Please help. Thank you
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Algebra.Com's Answer #11725 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Your equations: \n" ); document.write( " x=5s x+y=100 5s=y+8 y/5=s \n" ); document.write( " 5(y/5)+y=100\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I think your equations should be: \n" ); document.write( " x=5s x+y=100 s+(x-y)=y+8 x/5=s \n" ); document.write( " y=100-x s+ x - 2y=8 \n" ); document.write( " y=100 - 5s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "s+x-2y = 8 \n" ); document.write( "s+ 5s -2(100-5s) = 8 \n" ); document.write( "6s -200 +10s = 8 \n" ); document.write( "16s -200=8 \n" ); document.write( "16s = 208 \n" ); document.write( "s= 13 son's age now \n" ); document.write( "x= 5(13) = 65 father's age now \n" ); document.write( "y=100-x = 100-65 = 35 my age now\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "\"When I am 65, I shall be five times as old as my son is now.\" ---- True!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"By then (I went from 35 to 65, so 30 years has gone by!), my son will be 8 years older than I am now.\" Son will be 13 + 30 = 43, which is 8 years older than I am now! ---- True!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"The combined ages of my father and myself are 100 years.\" ---- True!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " \n" ); document.write( " |