document.write( "Question 159122: These equation has more than 2 solutions.
\n" ); document.write( "27x^3-8=0 Help. What do I do since it is a cube not square
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Algebra.Com's Answer #117243 by midwood_trail(310)\"\" \"About 
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27x^3 -8 = 0 \r
\n" ); document.write( "\n" ); document.write( "Add 8 to both sides.\r
\n" ); document.write( "\n" ); document.write( "27x^3 = 8\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 27.\r
\n" ); document.write( "\n" ); document.write( "x^3 = (8/27)\r
\n" ); document.write( "\n" ); document.write( "We now take the CUBE ROOT of both sides.\r
\n" ); document.write( "\n" ); document.write( "Final answer is x = 2/3\r
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