document.write( "Question 159119: The sum of three consecutive integers is 47 less than the least of the integers. Find the integers.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #117237 by midwood_trail(310)![]() ![]() ![]() You can put this solution on YOUR website! Let x = first integer.\r \n" ); document.write( "\n" ); document.write( "Then: x + 1 = second integer and x + 2 = third integer\r \n" ); document.write( "\n" ); document.write( "The least of the integers is x.\r \n" ); document.write( "\n" ); document.write( "We add all three and then equate the sum to x - 47.\r \n" ); document.write( "\n" ); document.write( "Where did x - 47 come from?\r \n" ); document.write( "\n" ); document.write( "In the question we read: \"...47 less than the least of the integers.\" Since the least of the integers is x, we subtract 47 from the x.\r \n" ); document.write( "\n" ); document.write( "x + x + 1 + x + 2 = x - 47\r \n" ); document.write( "\n" ); document.write( "3x + 3 = x - 47\r \n" ); document.write( "\n" ); document.write( "3x - x = -47 - 3\r \n" ); document.write( "\n" ); document.write( "2x = -50\r \n" ); document.write( "\n" ); document.write( "x = -50/2\r \n" ); document.write( "\n" ); document.write( "x = -25...This is the first integer.\r \n" ); document.write( "\n" ); document.write( "x + 1 = -25 + 1 = -24...This is the second integer.\r \n" ); document.write( "\n" ); document.write( "x + 2 = -25 + 2 = -23...This is the third integer.\r \n" ); document.write( "\n" ); document.write( "Notice that they are consecutive: one comes right after the other.\r \n" ); document.write( "\n" ); document.write( "Did you follow?\r \n" ); document.write( "\n" ); document.write( "P.S. The number -25 the furthest away from zero on the number line. This is why is the smallest of the three integers.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |