document.write( "Question 159081: The average price of 3 mugs is $4, one of the mugs cost $p and another mug cost $3...express the price of the 3rd mug in terms of p... \n" ); document.write( "

Algebra.Com's Answer #117200 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
By $\"Averaging\"$ :
\n" ); document.write( " $\"%28M%5B1%5D%2BM%5B2%5D%2BM%5B3%5D%29%2F3=4\"$ ------> working eqn
\n" ); document.write( " $\"Price\"$ :
\n" ); document.write( " $\"M%5B1%5D\"$ = $p1
\n" ); document.write( " $\"M%5B2%5D\"$ = $3
\n" ); document.write( " $\"M%5B3%5D\"$ = $p2
\n" ); document.write( "Substituting:
\n" ); document.write( " $\"%28p%5B1%5D%2B3%2Bp%5B2%5D%29%2F3=4\"$
\n" ); document.write( " $\"p%5B1%5D%2B3%2Bp%5B2%5D=3%2A4\"$
\n" ); document.write( " $\"p%5B2%5D=12-3-p%5B1%5D\"$
\n" ); document.write( " $\"p%5B2%5D=9-p%5B1%5D\"$ -----------------> ANSWER, price of 3rd Mug
\n" ); document.write( ". By knowing price$ of $\"M%5B1%5D\"$ , you can get price$ of $\"M%5B3%5D\"$ by subtacting from $9.00
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
\n" ); document.write( " \n" ); document.write( "

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