document.write( "Question 21824: 3+y/4=-y/8 \n" ); document.write( "
Algebra.Com's Answer #11719 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"3%2By%2F4=-y%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by the LCD of the problem which is 8. This clears the fractions:
\n" ); document.write( "\"+8%2A3+%2B+8%2A%28y%2F4%29+=+8%2A%28-y%2F8%29+\"
\n" ); document.write( "\"24+%2B+2y+=+-y+\"\r
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\n" ); document.write( "\n" ); document.write( "Subtract 2y from each side:
\n" ); document.write( "\"24%2B2y-2y+=+-y+-2y+\"
\n" ); document.write( "\"24+=+-3y\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by -3:
\n" ); document.write( "\"24%2F-3+=+%28-3y%29%2F-3\"
\n" ); document.write( "\"-8=y\"\r
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\n" ); document.write( "\n" ); document.write( "You might want to check this:\r
\n" ); document.write( "\n" ); document.write( "\"3+%2B+%28-8%29%2F4+=+8%2F8\"
\n" ); document.write( "\"3-2+=+1\"
\n" ); document.write( "It checks.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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