document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159046>Question 159046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a block of aluminum occupies a volume of 15.0 cm^3 and has a mass of 40.5 g. what is the density, in g/cm^3, of this metal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117180 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a block of aluminum occupies a volume of 15.0 cm^3 and has a mass of 40.5 g. what is the density, in g/cm^3, of this metal?<BR>\n" );
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document.write( "2 terms are given, grams and cm^3 (cc)<BR>\n" );
document.write( "Divide the grams by the cc to get g/cc.<BR>\n" );
document.write( "40.5 g/15 cc = 2.7 g/cc\r<BR>\n" );
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