document.write( "Question 159069This question is from textbook
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document.write( ": 2 years ago Paul was 7 times as old as Matt. 2 years from now, Paul will be 5 times as old is Matt. How old are Paul and Matt? I do have the answer, but can't come up with the correct equation.\r
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document.write( "TIA \n" );
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Algebra.Com's Answer #117167 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! let P = paul's age now. \n" ); document.write( "let M = Matt's age now. \n" ); document.write( "2 years ago Paul was 7 times as old as Matt (was then is implied but not stated). \n" ); document.write( "2 years ago Paul will be 5 times as old as Matt (will be then is implied but not stated). \n" ); document.write( "equations become \n" ); document.write( "P-2 = 7*(M-2) = 7*M - 14 \n" ); document.write( "P+2 = 5*(M+2) = 5*M + 10 \n" ); document.write( "adding 2 to both sides of the first equation and subtracting 2 from both sides of the second equation and they become \n" ); document.write( "P = 7*M - 14 + 2 = 7*M - 12 \n" ); document.write( "P = 5*M + 10 - 2 = 5*M + 8 \n" ); document.write( "since they both equal the same thing they are equal to each other so they become \n" ); document.write( "7*M - 12 = 5*M + 8 \n" ); document.write( "solving for M, equation becomes \n" ); document.write( "2*M = 20 \n" ); document.write( "M = 10 \n" ); document.write( "substituting for M in the first equation gets \n" ); document.write( "P = 7*M - 12 \n" ); document.write( "P = 7*10 - 12 \n" ); document.write( "P = 70 - 12 \n" ); document.write( "P = 58 \n" ); document.write( "substituting for P and M in the second equation gets \n" ); document.write( "P = 5*M + 8 \n" ); document.write( "58 = 5*10 + 8 \n" ); document.write( "58 = 58 \n" ); document.write( "values for P and M are good. \n" ); document.write( "answer is \n" ); document.write( "P = 58 \n" ); document.write( "M = 10 \n" ); document.write( " |