document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=159067>Question 159067</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two consecutive integers such that three times the first equals twice the second.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #117147 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=117147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Integer 1=X Integer 2= X=1. A consecutive number would be the next one. ie 1,2,3 etc. \r<BR>\n" );
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document.write( "3X=2(X+1)    Use the distributive property. 3X=2X+2<BR>\n" );
document.write( "Subtract 2X from 3X =  X=2 therfore the consecutive #'s are 2 and 3. To double check replace integers into the equation: (3)(2)=2(3) </SPAN>\n" );
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